-3x+19=-x^2+1

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Solution for -3x+19=-x^2+1 equation: 



-3x+19=-x^2+1

We move all terms to the left:

-3x+19-(-x^2+1)=0

We get rid of parentheses

x^2-3x-1+19=0

We add all the numbers together, and all the variables

x^2-3x+18=0

a = 1; b = -3; c = +18;
Δ = b2-4ac
Δ = -32-4·1·18
Δ = -63
Delta is less than zero, so there is no solution for the equation

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